1.

For a weak acid HA with dissociation constant 10^(-9), pOH of its 0.1 M solutions is

Answer»

9
3
11
10

Solution :Dissociation constant of `HA = 10^(-9)`
`HA hArr H^(+) + A^(-)`
`[H^(+)] = sqrt((K_(a))/(C)) = sqrt((10^(-9))/(0.1)) , [H^(+)] = 10^(-4)`
`:. PH = 4`
`because pH + POH = 14`
`pOH = 14- pH = 14-4 , pOH = 10` .


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