For an abrupt PN junction diode, small signal capacitance is 1nF/cm^2 at zero bias condition.If the built in voltage, Vbi is 1V, the capacitance at reverse bias of 99V is?(a) 0.1nF/cm^2(b) 1nF/cm^2(c) 1.5nF/cm^2(d) 2nF/cm^2This question was addressed to me in examination.I need to ask this question from Diode Capacitances in section Semiconductor-Diode Characteristics of Electronic Devices & Circuits

For an abrupt PN junction diode, small signal capacitance is 1nF/cm^2

1.	For an abrupt PN junction diode, small signal capacitance is 1nF/cm^2 at zero bias condition.If the built in voltage, Vbi is 1V, the capacitance at reverse bias of 99V is?(a) 0.1nF/cm^2(b) 1nF/cm^2(c) 1.5nF/cm^2(d) 2nF/cm^2This question was addressed to me in examination.I need to ask this question from Diode Capacitances in section Semiconductor-Diode Characteristics of Electronic Devices & Circuits
Answer» The correct answer is (a) 0.1nF/cm^2 Easiest EXPLANATION: CJO is the capacitance at zero bias, that is VR=0V, Cjo=CJ for VR=0V. We know, Cj = Cjo/(1+(VR/Vbi))m , m=1/2 for ABRUPT. So, puttingCj=0.1nF/cm^2 where, VR=99V andVbi=1V we GET, Cjo= 0.1(1+99)^1/2 = 0.1nF/cm^2.

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