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For an AC given by I = 50cos(100 t + 45^@)A. The value of rms = ..... A.

Answer»

`50sqrt2`
`25sqrt2`
`25`
0

Solution :By comparing `I=50cos (100t+45^@)` with `I=I_m COS (omegat+phi)`
`I_m`=50 A
`therefore I_(RMS)=I_m/sqrt2=50/sqrt2=25sqrt2` A


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