1.

For an amplifier in C.E. configuration for load 1kOmega (h_(fe)=50) and (h_("cc")=25xx10^(-6)) , the current gain is :

Answer»

`-48.78`
`-24.8`
`-15.7`
`-5.2`

SOLUTION :SEMICONDUCTOR
`A_i=(h_(fe))/(1+h_(CE)R_L)`
Here , `h_(fe)=50`
`h_(ce)=25xx10^(-6)`
`R_L=10000Omega`
`:. A_i=50/(1+25xx10^(-6)xx10^3)`
`=50/(1+0.25)=50/(1.025)=48.78(-ve)`


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