For an aqueous solution freezing point is – 0.186∘C. Elevation of – InterviewSolution

1.	For an aqueous solution freezing point is – 0.186∘C. Elevation of the boiling point of the same solution is (Kf =1.86 mole−1 kg and Kb = 0.512 mole−1 kg)
Answer» For an aqueous solution freezing point is – ${0.186}^{\circ} C$ . Elevation of the boiling point of the same solution is ( $K_{f}$ =1.86 $m o l e^{- 1}$ kg and $K_{b}$ = 0.512 $m o l e^{- 1}$ kg)

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