1.

For an electron having s=1//2, the spin anglar momentum is

Answer»

`(SQRT(3)H)/(4PI)`
`sqrt(3)`
`sqrt(2)`
`1`

Solution :SPIN angular MOMENTUM`=sqrt(s(s+1))h/(2pi)`
for s=1/2
Spin angular momentum `=sqrt(1/2(1/2+1)). h/(2pi)`
`=sqrtS(1/2xx3/2). h/(2pi)=(sqrt(3).h)/(4pi)`


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