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For an equilateral prism made of a material of Refractive index sqrt2, find the angle of minimum deviation for a ray of monochromatic light. |
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Answer» SOLUTION :`n=SQRT2` and `A=60^@` `n=[SIN(A+D)/2]/(sinA/2) sqrt2=[sin(60+D)/2]/SIN30^@` `sqrt2/2=sin(60+D)/2 1/sqrt2=sin((60+D)/2)` `(60+D)/2=45, D=30^@` |
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