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    				| 1. | For an ideal gas, consider only `P-V` work in going from an initial state `X` to the final state `Z`. The final state `Z` can be reached by either of the two paths shown in the figure. Which of the following choice(s) is (are) correct? [Take `DeltaS` as change in entropy and `w` as work done] A. `DeltaS_(XtoZ)=DeltaS_(XtoY)+DeltaS_(YtoZ)`B. `w_(XtoZ)=w_(XtoY)+w_(YtoZ)`C. `w_(XtoYtoZ)=w_(XtoY)`D. `DeltaS_(XtoYtoZ)=DeltaS_(XtoY)` | 
| Answer» Correct Answer - A::C `DeltaS` is a state function. So, it does not depend on path and only depends on initial and final stages. `DeltaS_(XtoZ)=Delta_(XtoY)+DeltaS_(YtoZ)` and `DeltaS_(YtoZ)` is not zero `:. DeltaS_(XtoYtoZ)!=DeltaS_(XtoY)` Work is not a state function and depends on path, `:. w_(XtoZ)=w_(XtoY)+w_(YtoZ)` `w_(XtoZ)=PdV` (`P` constant) `w_(YtoZ)=0` (`V` is constant) `w_(XtoZ)=2.303nRT"log"(V_(2))/(V_(1))` `w_(XtoYtoZ)=w_(XtoY)+w_(YtoZ)` As `w_(YtoZ)=0`, hence `w_(XtoYtoZ)=w_(XtoY)` | |