For an ideal gas, the work of reversible expansion under isothermal condition can be calculated by using expression ` = -nRT ln.(V_(f))/(V_(i))`. A sample containing 1.0 mol of an ideal gas is expanded isothermally and reversible to ten times of its original volume, in two separate experiments. The expansion is carried out at 300 K and at 600 K respectively. Choose the correct optionA. Work done at 600 K is 20 times the work done at 300 KB. work done at 300K is twice the work done at 600 KC. work done at 600 K is twice the work done at 300 KD. `Delta U = 0` in both cases

For an ideal gas, the work of reversible expansion under isothermal co

1.	For an ideal gas, the work of reversible expansion under isothermal condition can be calculated by using expression ` = -nRT ln.(V_(f))/(V_(i))`. A sample containing 1.0 mol of an ideal gas is expanded isothermally and reversible to ten times of its original volume, in two separate experiments. The expansion is carried out at 300 K and at 600 K respectively. Choose the correct optionA. Work done at 600 K is 20 times the work done at 300 KB. work done at 300K is twice the work done at 600 KC. work done at 600 K is twice the work done at 300 KD. `Delta U = 0` in both cases
Answer» Correct Answer - C::D `w = -nRT ln.(V_(f))/(V_(i))` Here, n, R and `ln.(V_(f))/(V_(i))` are same in both the cases therefore `(w_(2))/(w_(1)) = (T_(2))/(T_(1))` or `(w(600K))/(w(300K)) = (600K)/(300K) = 2`

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