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For an inductor having self inductance 4.6 H, emf induced in it for time interval from 5 ms to 6 ms is ……

Answer»

ZERO
`10^3` V
`-23xx10^3` V
`23xx10^3` V

Solution :Here `(dI)/(dt)` = slope of `bar(BC)`
`=(0-5)/(1xx10^(-3))=-5xx10^3 A/s`
Now , self induced emf is,
`epsilon=-L (dI)/(dt)`
=-(4.6)`(-5xx10^3)`
`THEREFORE epsilon=23xx10^3` V


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