For an ionic solid MX_(2), where X is monovalent, the enthalpy of formation of the enthalpy of formation of the solid from M (s) and X_(2) (g) is 1.5 times the electron gain enthalpy of X(g). The first and second ionisation enthalpies of the meta (M) are 1.2 and 2.8 times of the enthalpy of sublimation of M(s). The bond dissociation enthalpy of X_(2) (g) is 0.8 times the first ionisation enthalpy of metal and it is also equal to one -fifth of the magnitude of lattice enthalpy of MX_(2). If the electron gain enthalpy of X (g) is -96 K cal//mol, the answer the enthalpy of sublimation of metal (M) in K cal/mol

For an ionic solid MX_(2), where X is monovalent, the enthalpy of form

1.	For an ionic solid MX_(2), where X is monovalent, the enthalpy of formation of the enthalpy of formation of the solid from M (s) and X_(2) (g) is 1.5 times the electron gain enthalpy of X(g). The first and second ionisation enthalpies of the meta (M) are 1.2 and 2.8 times of the enthalpy of sublimation of M(s). The bond dissociation enthalpy of X_(2) (g) is 0.8 times the first ionisation enthalpy of metal and it is also equal to one -fifth of the magnitude of lattice enthalpy of MX_(2). If the electron gain enthalpy of X (g) is -96 K cal//mol, the answer the enthalpy of sublimation of metal (M) in K cal/mol
Answer» SOLUTION :`{:(M(s) RARR M(g)""DeltaH=X),(M(g) rarr M^(+)(g)""DeltaH=1.2 x),(M^(+)(g) rarrM^(2+)(g)""DeltaH=2.8 x),(X_(2) rarr 2X(g)""DeltaH=0.8xx1.2 x=1/5 z),(2X(g) rarr 2X^(-) (g)""DeltaH=-2y),(M^(2+)(g)+2X^(-) (g) rarr MX_(2)(s)""DeltaH=-z=-4.8x),(BAR(M(s)+X_(2)(g) rarr MX_(2)(s)""DeltaH=-1.5 y"")):}` `x+4x+0.96x-2y-4.8 x=-1.5 y` `1.16x=+0.5 y""rArrx=(0.5xx96)/(1.16)=41.38`