1.

For an isosceles prism of angle A and refractive index mu it is found that the angle of minimum deviation delta_(m)=A.Which of the following options is/ are correct?

Answer»

At minimum deviation, the incident angle `i_(1)` and the refracting angle `r_(1)` at the first refracting surface are related by `r_(1)=(i_(1)//2)`
For this prism, the refractive index `mu` and the angle of prism A are related as `A=1/2 cos^(-1) (mu/2)`
For the angle of INCIDENCE `i_(1) = A`, the ray inside the prism is PARALLEL to the base of the prism
For this prism, the emergent ray at the SECOND surface will be tangential to the surface when the angle of incidence at the first surface is `i_(1)=SIN^(-1) [sin A sqrt(4"cos"^(2) A/2 -1)-cos A]`

Answer :A::C::D


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