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For an isotropic antenna, the average power Pavcan be expressed in terms of radiated power Pr as ____(a) Pav=Pr/4π(b) Pav=Pr/2πr^2(c) Pav=Pr/2π(d) Pav=Pr/4πr^2The question was asked in an online interview.I'm obligated to ask this question of Directive Gain topic in chapter Antenna Parameters of Antennas |
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Answer» RIGHT option is (d) Pav=Pr/4πr^2 For explanation I WOULD say: Average power is the TOTAL power radiated in the unit area. Here for isotropic radiation, area is spherical (say with radius R) and the area is 4πr^2. ∴ Pav=Pr/4πr^2 |
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