1.

For an n-p-n transistorpercentage of electronsemitted reaching the collector is 80% if th ecollectcurrentis 1 mA

Answer»

the EMITTER CURRENT is 1.5 mA
the base current is 0.5 mA
the emitter curretn is 1.25 mA
the base current is 0.25 mA

Solution :Given `I_(e) = 80% `of `I_(Q)`
`rArrI_(e) = (10)/(8)I_(c )`
Given `I_(e) = 1 mA`
`I_(b) = I _(e)- I_(e)`
`=(1.25 -1) mA = 0 .25 mA`
Henceoption (c ) and (d) are correct.


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