1.

For an van der Waals' gas, the term ((ab)/(V^(2))) represents some

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pressure
energy
critical DENSITY
molar mass

Solution :For `(ab)/(V^(2))` a and b are VADER Waals. constants
Unit of `a=("atm". L^(2))/(("MOLE")^(2))` Unit of b `=L/("mole")`
V=volume of gas per mole =L/mole
So `(ab)/(V^(2))=(("atm".L^(2))/(("mole")^(2))xxL/("mole"))/((L//"mole")^(2))=("atm"L)/("mole")`
it is the unit of energy.


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