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For angles of projection of a projectile at angle `(45^(@) - theta) and (45^(@)+ theta)`, the horizontal ranges described by the projectile are in the ratio of :A. `2:1`B. `1:2`C. `1:1`D. `2:3` |
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Answer» Correct Answer - c For a projectile launched with velocity u at an angle `theta`, the horizontal range is given by `R=(u^(2)sin 2 theta)/g` (i) for `theta_(1)=45^(@)- theta` `R_(1)=(u^(2)sin (90^(@)-2 theta))/g=(u^(2)cos 2 theta)/g` (ii) For `theta_(2)=45^(@)+ theta` |
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