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For any base show that log(1 + 2 + 3) = log 1 + log 2 + log 3 |
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Answer» L.H.S. = log(1 + 2 + 3) = log 6 R.H.S. = log 1 + log 2 + log 3 = 0 + log (2 × 3) = log 6 ∴ L.H.S. = R.H.S. |
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