1.

For any base show that log(1 + 2 + 3) = log 1 + log 2 + log 3

Answer»

L.H.S. = log(1 + 2 + 3) = log 6

R.H.S. = log 1 + log 2 + log 3

= 0 + log (2 × 3)

= log 6

∴ L.H.S. = R.H.S.



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