1.

For any given series of spectral lines of atomic hydrogen let Deltabar(v)=bar(v)_("max") fl bar(v)_("min")be the difference in maximum and minimum frequencies in

Answer»

`4:1`
`9:4`
`5:4`
`27:5`

Solution :`bar(v)PROP DeltaE`
For H - atom
`bar(v)=R[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
For Lyman SERIES,
`bar(v)" (MAX)"=13.6(1-(1)/(oo))`
`bar(v)" (min)"=13.6(1-(1)/(4))`
`therefore""bar(v)_("max")-bar(v)_("min")=13.6((1)/(4))`
For Balmer series,
`bar(v)(max)=13.6((1)/(4)-(1)/(oo))`
`bar(v)(min)=13.6((1)/(4)-(1)/(6))`
`therefore bar(v)_("max")-bar(v)_("min")=13.6((1)/(9))`
`(Deltabar(v)_("Lyman"))/(Deltabar(v)_("Balmer"))=(9)/(4)`


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