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For any instance, XK+1 is(a) Xk + h(b) Xk + t(c) Xk + X(d) Xk + X1I have been asked this question in exam.Asked question is from Numerical Method in division Rigorous Distillation Calculations of Distillation Design

Answer»

The correct choice is (a) Xk + h

For explanation I would SAY: For any INSTANCE XK+1 is Xk + h, where h is the COMMON difference and Xk is the PREVIOUS calculated VALUE of series.



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