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For coagulating 200 mL of arsenious sulphide sol, 10 mL of 1M NaCl solution is required. Find out the flocculation volum of NaCl. |
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Answer» Solution :10 mL of 1 M NaCl solution contain 10 milli-moles Now, 200 mL of arsenious sulphide `(As_(2)S_(3))` REQUIRE for COAGULATION NaCl = 10 milli-moles 100 mL of solution require for coagulation `NaCl=(10)/(100)xx1000=50` milli-moles |
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