For common emitter circuit of a transistor , when the base current changes by 80 muA, the collector current change by 4.8 mA. Then the current amplification factor will be :

For common emitter circuit of a transistor , when the base current cha

1.	For common emitter circuit of a transistor , when the base current changes by 80 muA, the collector current change by 4.8 mA. Then the current amplification factor will be :
Answer» 120 30 60 none of these Solution :`BETA = ((DeltaI_c)/(DeltaI_b))=(4.8xx10^(-3))/(80xx10^(-6))=60`

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For common emitter circuit of a transistor , when the base current changes by 80 muA, the collector current change by 4.8 mA. Then the current amplification factor will be :

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