1.

For complete combustion of ethanol, C_(2)H_(5)OH(l)+3O_(2)(g)rarr2CO_(2)(g)+3H_(2)O(l),the amount of heta producedas measured in bomb calorimeter, is 1364.47 kJ mol^(-1) at 25^(@). Assuming ideality the Enthalpy of combustion. Delta_(C)H, for the reaction will be(R=8.314 kJ mol^(-1))

Answer»

`-1366. 95 kJ mol^(-1)`
`-1361.95 kJ mol^(-1)`
`-1460.50 kJ mol^(-1)`
`-1350.50 kJ mol^(-1)`

SOLUTION :`C_(2)H_(5)OH(l)+3O_(2)(g)rarr2CO_(2)(g)+3H_(2)O(l)`
`DeltaU=-1364.47 KJ//mol`
`DeltaH=DeltaU+Deltan_(g)RT`
`Deltan_(g)=-1`
`DeltaH=-1364.47+[(-1xx8.314xx298)/(1000)]`
`=-1364.47-2.4776`
`=-1366.94 KJ//mol`.


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