1.

For complete neutralization of HCl with NaOH, the heat of neutralization is

Answer»

`+13.70 kJ mol^(-1)`
`-13.70 kJ mol^(-1)`
`-57.32 kJ mol^(-1)`
`-57.32 kJ mol^(-1)`

Solution :HEAT of NEUTRALIZATION of strong ACID and strong base is equal to the `-57.32 kJ mol^(-1)`.


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