1.

For converting a solution if 100 ml KCl of 0.4 M concentration into a solution of KCl 0.05 M concentration. The quantity of water added is

Answer»

900 ML
700 ml
500 ml
300 ml

Solution :We know that, `M_(1)V_(1)= M_(2)V_(2)`
`0.05xx V_(1)=0.4xx100`
`therefore V_(1)=(0.4xx100)/(0.05)=800`
`V_(2)-V_(1)=800-100 RARR 700 ml`.


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