1.

For d-electrons the orbital angular momentum is

Answer»

`sqrt(6)h/(2PI)`
`sqrt(2)h/(2pi)`
`h/(2pi)`
`2 h/(2pi)`

SOLUTION :ORBITAL angular MOMENTUM `=sqrt(l(l+1))h/(2pi)`
For d l=2
`:.` Orbital angular momentum
`=sqrt(2(2+1))h/(2pi)=sqrt(6)h/(2pi)`


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