1.

For dibasic acid correct order is

Answer»

`K_(a1) lt K_(a2)`
`K_(a1) gt K_(a2)`
`K_(a1)=K_(a2)`
not certain

Solution :In DIBASIC acids the loss of second proton occurs much less readily than the FIRST. Usually the `K_(a)` values for successive loss of protons from these acids DIFFER by at least a factor of `10^(-3) i.e., K_(a_(1)) gt K_(a_(2))`
`H_(2)X hArr H^(**) ** HX^(**) K_(3_(1))`
`HX^(**) hArr H^(**) ** X^(@**) K_(a_(2))`


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