1.

For [FeF_(6)]^(3-)" and "[CoF_(6)]^(3-), the statement that is correct is :

Answer»

both are COLOURED
both are colourless
`[FeF_(6)]^(3-)` is coloured and `[CoF_(6)]^(3-)` is colourless
`[FeF_(6)]^(3-)` is colourless and `[CoF_(6)]^(3-)` is coloured

Solution :Both have UNPAIRED ELECTRON.


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