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For given metal plate threshold frequency is V_(0). When radiation of 2V_(0) is incident on metal surface ,maximum velocity of photoelectron emitted is V_(1) when frequency of incident radiation is charged to 5V_(0) ,maximum velocity of photoelectron emitted is v_(2).Ration of v_(1) and v_(2) is ..... |
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Answer» Solution :From Einstein equation `(1)/(2)mv_(1)^(2)=h(2v_(0))-hv_(0)` `therefore (1)/(2)mv_(1)^(2)=hv_(0)`…..(1) and `(1)/(2)mv_(1)^(2)=h(5v_(0))-hv_(0)` `(1)/(2)mv_(2)^(2)=4hv_(0)`……..(2) `therefore` TAKING ratio of (1) and (2) , `((v_(1)^(2))/(v_(2)^(2)))=(1)/(4)` `therefore (V_(1))/(v_(2))=SQRT((1)/(4))=(1)/(2)` `therefore` Ratio of `v_(1)` and `v_(2)` is 1:2 |
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