1.

For H^(+) , lambda^(0) = 349.8 S cm^(2) mol^(-1) . Calculatethe velocity of H^(+) electrodes are 5 cm apart to which 1 volt of potential is applied. If the answer is 7.0 xx 10^(-x)cm/s then x is -

Answer»


SOLUTION :VELOCITY of `H^(oplus)`=(Ionic mobility ` xx ` potential gradient )
` = ((^^_M^(0))/(F)) xx (("VOLTAGE")/("distance")) = (349.8 S - cm^(2) - " MOLE"^(-1))/(96500) xx (1" volt")/(5 cm ) = 7.249 xx 10^(-4) cm//sec`


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