1.

For hypothetical reactions, the equlibrium constnat (k) vlues are given AhArrB,K_(1)=2.0 BhArrC,K_(2)=4.0 ChArrD,K_(3)=3.0 The equlibrium constnat for reaction AhArrD is

Answer»

48
6
`2.7`
12

Solution :`K_(1)=([B])/([A])=2.00,K_(2)=([C])/([B])=4.00 K_(3)=([D])/([C])=3.00`
For the reaction `A hArrD`
`K=([D])/([A])=([D])/([C])xx([C])/([B])xx([B])/([A])=K_(1)xxK_(2)xxK_(3)=3xx4xx2=24`


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