For intensity `I` of a light of wavelength `5000 Å` the photoelectron saturation current is `0.40 mu A` and stopping potential is `1.36 V` , the work function of metal isA. `2.47 eV`B. `1.36 eV`C. `1.10 eV`D. `0.43 eV`

For intensity `I` of a light of wavelength `5000 Å` the photoelectron

1.	For intensity `I` of a light of wavelength `5000 Å` the photoelectron saturation current is `0.40 mu A` and stopping potential is `1.36 V` , the work function of metal isA. `2.47 eV`B. `1.36 eV`C. `1.10 eV`D. `0.43 eV`
Answer» Correct Answer - C By using `E = W_(0) + K_(max)` `rArr E = (12375)/(5000) = 2.475 eV` and `K_(max) = eV_(0) = 1.36 eV` So `2.475 = W_(0) + 1.36 rArr W_(0) = 1.1 eV`

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For intensity `I` of a light of wavelength `5000 Å` the photoelectron saturation current is `0.40 mu A` and stopping potential is `1.36 V` , the work function of metal isA. `2.47 eV`B. `1.36 eV`C. `1.10 eV`D. `0.43 eV`

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