1.

For L-R circuit, the time constant is equal to

Answer»

twice the RATIO of the ENERGY strored in the magnetic FIELD to the rate of dissipation of energy in the resistance
the ratio of the energy STORED in the magnetic field to the rate of dissipation of energy in the resistance.
half of the ratio of the energy stored in the magnetic field to the rate of dissipation of energy in the resistance
square of the ratio of the energy stored in the magnetic field to the rate of dissipation of energy in the resistance

Solution :`tau=(2xx1/2LI^(2))/(I^(2)R)=L/R`


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