1.

For light incident from air onto a slab of refractive index 2. Maximum possible angle of refraction is,

Answer»

`30^(@)`
`45^(@)`
`60^(@)`
`90^(@)`

Solution :From Snell.s law, `mu =(sini)/(SINR)`
Now consider an ANGLE of incident is `90^(@)`
`sinr=(SIN90^(@))/(2)`
R=`SIN^(-1)(0.5)`
`r=30^(@)`


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