Saved Bookmarks
| 1. |
For mixed connection shown in figure derive equation of equivalent resistance. |
Answer» Solution :`rArr` As SHOWN in figure `R_(2) and R_(3)` are connected in PARALLEL with B and C and with this `R_(1)` is connected between A and B.  where R. = EQUIVALENT resistance of `R_(2) and R_(3)` connected in parallel. `THEREFORE (1)/(R.) = (1)/(R_(2)) + (1)/(R_(3)) ` `R. = (R_(2) R_(3))/(R_(2) + R_(3)) ""` ... (1) `rArr` Equivalent resistance of all three RESISTORS, `R_(eq) = R_(1) + R.` `= R_(1) + (R_(2) R_(3))/(R_(1) + R_(3)) "" ` ... (2) `rArr` Let voltage between A and C be v, then current through`R_(1)`, `I = (V)/(R_(eq)) = (V)/(R_(I) + (R_(2) R_(3))/(R_(2) + R_(3))) ` `therefore I = (V(R_(2) + R_(3)))/(R_(1) R_(2) + R_(1) R_(3) + R_(2)R_(3))` 
|
|