1.

For monoatomic gases gamma = 1.66 pm pm 0.01. Find specific heats of helium and of neon.

Answer»


Solution :It follows from the relations `C_(mp) - C_(mv) = R` and `gamma = (C_(mp))/(C_(mv))` that `C_(mv) = R/(gamma - 1)` . Hence the molar HEAT of a monoatomic gas at constant volume LIES within the limits
`1.24 xx 10^4 le C_(mv) le 1.28 xx 10^(4) ` J/(kmole.K).
Accordingly
`2.07 xx 10^4 le C_(mp) le 2.11 xx 10^4 ` J/(kmole.K)`.
To OBTAIN the specific heats, divide the molar heats by the molar MASS.


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