For N_2O_5 to 2NO_2 + 1//2O_2, it is found that (-d)/(dt) [N_2O_5] = k – InterviewSolution

1.	For N_2O_5 to 2NO_2 + 1//2O_2, it is found that (-d)/(dt) [N_2O_5] = k_1[N_2O_5], (d)/(dt) [NO_2] = k_2[N_2O_5], (d)/(dt) [O_2] = k_3[N_2O_5] , then
Answer» `k_1 = 2k_2 = 3k_3` `2k_1 = 4k_2 = k_3` `2k_1 = k_2 = 4k_3` `k_1 = k_2 = k_3` ANSWER :C

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