InterviewSolution
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For `n in Z ,`the general solution of `(sqrt(3)-1)sintheta+(sqrt(3)+1)costheta=2i s(n in Z)``theta=2npi+-pi/4+pi/(12)``theta=npi+(-1)^npi/4+pi/(12)``theta=2npi+-pi/4``theta=npi+(-1)^npi/4-pi/(12)`A. `theta=2npi pm pi/4+pi/12`B. `theta=n pi +(-1)^(n) pi/4+pi/12`C. `theta=2npi pm pi/4`D. `theta=npi +(-1)^(n) pi/4- pi/12` |
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Answer» Correct Answer - A `(sqrt(3)-1) sin theta+(sqrt(3)+1) cos theta=2` or `((sqrt(3)-1))/(2sqrt(2)) sin theta+ ((sqrt(3)+1)/(2sqrt(2))) cos theta=1/sqrt(2)` or `"sin" pi/12 sin theta+"cos"pi/12 cos theta= "cos"pi/4` or `cos(theta-pi/12)="cos" pi/4` `rArr theta-pi/12=2npi pm pi/4, n in Z` or `theta=2npi pm pi/4+ pi/12, n in Z` |
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