1.

For non-zero vectors bara,barb,barc,abs(baraxxbarb.barc)=abs(bara)abs(barb)abs(barc) holds if and only if

Answer»

`bara.barb=barb.barc=barc.bara=0`
`bara.barb+barb.barc+barc.bara=0`
`bara+barb+barc=0`
`[BARABARBBARC]=0`

ANSWER :A


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