1.

For one coil, kept in 1T external magnetic field, current passing through it increases from 1 A to 2 A in 2 xx 10^(-3) s. Meanwhile time rate of change of its area is found to be 5 "m"^2/"ms" . Then the self inductance of the coil is ____

Answer»

2 H
5 H
10 H
20 H

Solution :We have `epsilon=-L (dI)/(dt)`
`therefore - (dPhi)/(dt)=-L (dI)/(dt)`
`therefore d/(dt)(NAB)=L(dI)/(dt)`
`therefore NB(DA)/(dt) =L (dI)/(dt)`
`therefore 1xx1xx5xx1/10^(-3)=L (2-1)/(2xx10^(-3))`
`therefore` L=10 H


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