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For one mole of an ideal gas, increasing the temperature from 10^(@)C to 20^(@)C |
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Answer» A) increases the average kinetic energy by TWO TIMES. Final temperature `=293K` `KE_(1)=(3RT_(1))/(2),KE_(2)=(3RT_(2))/(2)` `(KE_(1))/(KE_(2))=(T_(1))/(T_(2))=(283)/(293)=0.96` `KE_(2)=1.04KE_(1)` `v_(rms)=sqrt((3RT)/(M))` `(v_(1))/(v_(2))=sqrt((T_(1))/(T_(2)))rArrsqrt((283)/(293))` `v_(2)=v_(1)sqrt((293)/(283))=1.02v_(1)` Both average K.E. and rms velocity increase but not significantly. |
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