1.

For photoelectric emission from certain metal the cutoff fequency is v.If radiation of frequency 2 v impinges on the metal plate,the maximum possible velocity of the emitted electron will be (m is the electron's mass),

Answer»

`SQRT((hv)/((2m)))`
`sqrt((hv)/(m))`
`sqrt((2hv)/(m))`
`2sqrt((hv)/(m))`

Solution :`(1)/(2)mv_(MVX)^(2)=h(2v)-hv` `THEREFORE v_(mvx)=sqrt((2hv)/(m))`


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