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For photoelectric emission from certain metal the cut - off frequency is `v`. If radiation of frequency `2 v` incident on the metal plate , the maximum possible velocity of the emitted electron will be (`m` is the electron mass).A. `sqrt(hv//(2m))`B. `sqrt(hv//m)`C. `sqrt(2hv//m)`D. `2sqrt(hv//m)` |
Answer» Correct Answer - C Cutoff frequency = v Work function `=phi =hv` Use, `E=K.E. +phi` `2hv=(1)/(2)mv^(2)+hv` `(1)/(2)mv^(2)=2hv-hv=hv` `v=sqrt((2hv)/(m))` |
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