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For plane waves in the air of frequency 1000 Hz and the displace amplitude `2xx10^(-8)m`, deduc (i) the velocity amplitude, and (ii) the intensity. (Take p= 1.3 kg//m^(3),c=340 m//s)` |
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Answer» `vmax("velocity amplitude")=aomega` `:.v_(max)=2xx10^(-8)xx(2pixx1000)=1.3xx10^(-4) m//s` `I=(1)/(2)pa^(2)omega^(2)c=(1)/(2)pv^(2)_(max)c` `implies I=(1)/(2)xx1.3(1.3xx10^(-4))^(2)xx340=3.7xx10^(-6) W//m^(2)` |
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