1.

For proton and alpha-particle,de-Broglie wavelength is same .For them……..will be equal .

Answer»

velocity
energy
frequency
momentum

Solution :`lambda_(p)=lambda_(alpha)IMPLIES(H)/(p_(p))=(h)/(p_(alpha))`
`therefore p_("proton")=p_(alpha)`
Momentum of proton and `alpha`-PARTICLE will be EQUAL.


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