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For Q. 25 find the minimum constant force to be applied to body of mass m_(1) in order to shift body of mass m_(2). Take m_(1)=m_(2)=10kg, mu=0.5 |
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Answer» Solution :`F.X=mum_(1)gx-1/2kx^(2)=0""...(i)` But `Kx=mu_(2)G.` (for just moving body of mass `m_(2))` Put the value of K in (i) to get F. F.x `-mum_(1)gx-1/2kx^(2)=0` But `kx=mum_(2)g` (for moving body of mass `m_(2)`) `Fx-mum_(1)gx-1/2((mum_(2)g)/(x))x^(2)=0` `F=mum_(1)g+1/2mum_(2)g` `=mu(m_(1)+(m_(2))/(2))g` `=0.5(10+10/2)10` `=75N` |
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