For R= 20 ohm and G= 0.8 mho, the attenuation constant will be(a) 16(b) 4(c) 2(d) 32The question was posed to me by my school teacher while I was bunking the class.The origin of the question is Lossless and Distortionless Line topic in chapter Transmission Lines of Electromagnetic Theory

For R= 20 ohm and G= 0.8 mho, the attenuation constant will be(a) 16(b

1.	For R= 20 ohm and G= 0.8 mho, the attenuation constant will be(a) 16(b) 4(c) 2(d) 32The question was posed to me by my school teacher while I was bunking the class.The origin of the question is Lossless and Distortionless Line topic in chapter Transmission Lines of Electromagnetic Theory
Answer» Correct choice is (B) 4 The best I can explain: The ATTENUATION constant is given by α = √(RG), where R and G is the resistance and conductance respectively. On SUBSTITUTING for R = 20 and G = 0.8, we get α = √(20 x 0.8) = 4 units.

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For R= 20 ohm and G= 0.8 mho, the attenuation constant will be(a) 16(b) 4(c) 2(d) 32The question was posed to me by my school teacher while I was bunking the class.The origin of the question is Lossless and Distortionless Line topic in chapter Transmission Lines of Electromagnetic Theory

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