1.

For reaction 2NOCl_((g))hArr2NO_((g))+Xl_(2(g)), K_(c)at 427^(@)Cis 3xx10^(-6)Lmol^(-1). The value of K_(p) is nearly

Answer»

<P>`7.50xx10^(-50)`
`2.50xx10^(-50)`
`2.50xx10^(-4)`
`1.72xx10^(-4)`

Solution :`2NOCl_((G))=2NO_((g))+Cl_(2(g))`
`K_(p)+K_(c)(RT)^(DELTAN)`
`K_(p)=3xx10^(-6)(0.0821xx700)=172.41xx10^(-6)=1.72xx10^(-4)`


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