1.

For same mass of two different ideal gases of molecular weights M_(1) and M_(2) plots oflog V vs lot P at a given constant temperature are shown. Identify the correct option

Answer»

`M_(1)gtM_(2)`
`M_(1)=M_(2)`
`M_(1)ltM_(2)`
Can be predicted only if temperature is known.

Solution :For IDEAL GASES
`PV=nRT=w/MRT "" ( :. n=w//M)`
For same mass of gases and at constant temperature wRT is constant (K).
`:.PV=K/M`
TAKING LOG both sides we get
`log P+logV="log"K/M`
`logV=-logP+"log"K/M`
comparing this with straight line equation
`y=mx+c`
For ideal gas 1, `("Intercept")_(1)="log"K/(M_(1))`
for ideal gas 2, `("Intercept")_(2)="log"K/(M_(2))`
`:. "log"K/(M_(2))gt"log"K/(M_(1))` (from GRAPH)
or `K/(M_(2))gtK/(M_(1))impliesM_(1)gtM_(2)`


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