1.

For sample of ""^(66)Cu, 7/8 of it decays in 15 min. The half-life of sample is:

Answer»

5 min
`7 /1 "min"`
10 min
14 min

Solution :`N=N_(0) e^(-lambdat)`
`N/N_(0)=(1/2)^(t/T)," here N"=1/8 N_(0) ("AMOUNT LEFT")`
`1/8=(1/2)^(t/T) RARR (1/2)^(3)=(1/2)^(t/T) therefore t/T=3`
`t=3T rArr 15 =3T therefore T=5"min"`


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