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For scattering by an .inverse square. field (such as that produced by a charged nucleus in Rutherford.s model), the relation between impact parameter b and the scattering angle theta is given by, b=(Ze^(2)cot theta//2)/(4pi epsilon_(0)((1)/(2)mv^(2))) What is the scattering angle for b = 0? |
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Answer» Solution :GIVEN relation: `b=(Ze^(2)cot theta//2)/(4pi epsilon_(0)((1)/(2)mv^(2)))` For b = 0, `0=(Ze^(2)cot theta//2)/(4pi epsilon_(0)((1)/(2)mv^(2)))` or `cot""(theta)/(2)=0 :. (theta)/(2)=90^(@)` or `theta=180^(@)` Thus the scattering angle is `180^(@)` when impact PARAMETER is zero. |
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